Swap Numbers Without Using Temporary Variables in C#

In this example, i’ll show you how to swap two numbers without using temporary variables in C#.

C# Code:


static void Main(string[] args)
        {
            int a = 5, b = 10;
            Console.WriteLine("Before swapping.");
            Console.WriteLine("a={0} b={1}",a,b);

            a = a + b;
            b = a - b;
            a = a - b;

            Console.WriteLine("After swapping.");
            Console.WriteLine("a={0} b={1}", a, b);

            Console.ReadKey();
        }

static void Main(string[] args)

{

int a = 5, b = 10;

Console.WriteLine("Before swapping.");

Console.WriteLine("a={0} b={1}",a,b);

a = a + b;

b = a - b;

a = a - b;

Console.WriteLine("After swapping.");

Console.WriteLine("a={0} b={1}", a, b);

Console.ReadKey();

}

Initially, a = 5 and b = 10.
Then, we add a and b and store it in a with the code a = a + b. This means a = 5 + 10. So, a = 15 now.
Then we use the code b = a - b. This means b = 15 - 10. So, b = 5 now.
Again, we use the code a = a - b. This means a = 15 - 5. So finally, a = 10.

Hence, the numbers have been swapped.

Output:


Before swapping.
a = 5, b = 10

After swapping.
a = 10, b = 5

Before swapping.

a = 5, b = 10

After swapping.

a = 10, b = 5

Swap Numbers Without Using Temporary Variables in C#

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